Integrand size = 34, antiderivative size = 102 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {a B x}{a^2+b^2}+\frac {b B \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}+\frac {a^4 B \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right ) d}-\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d} \]
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Time = 0.29 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.206, Rules used = {21, 3647, 3728, 3708, 3698, 31, 3556} \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {b B \log (\cos (c+d x))}{d \left (a^2+b^2\right )}+\frac {a B x}{a^2+b^2}+\frac {a^4 B \log (a+b \tan (c+d x))}{b^3 d \left (a^2+b^2\right )}-\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d} \]
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Rule 21
Rule 31
Rule 3556
Rule 3647
Rule 3698
Rule 3708
Rule 3728
Rubi steps \begin{align*} \text {integral}& = B \int \frac {\tan ^4(c+d x)}{a+b \tan (c+d x)} \, dx \\ & = \frac {B \tan ^2(c+d x)}{2 b d}+\frac {B \int \frac {\tan (c+d x) \left (-2 a-2 b \tan (c+d x)-2 a \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx}{2 b} \\ & = -\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d}+\frac {B \int \frac {2 a^2+2 \left (a^2-b^2\right ) \tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{2 b^2} \\ & = \frac {a B x}{a^2+b^2}-\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d}+\frac {\left (a^4 B\right ) \int \frac {1+\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b^2 \left (a^2+b^2\right )}-\frac {(b B) \int \tan (c+d x) \, dx}{a^2+b^2} \\ & = \frac {a B x}{a^2+b^2}+\frac {b B \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}-\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d}+\frac {\left (a^4 B\right ) \text {Subst}\left (\int \frac {1}{a+x} \, dx,x,b \tan (c+d x)\right )}{b^3 \left (a^2+b^2\right ) d} \\ & = \frac {a B x}{a^2+b^2}+\frac {b B \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}+\frac {a^4 B \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right ) d}-\frac {a B \tan (c+d x)}{b^2 d}+\frac {B \tan ^2(c+d x)}{2 b d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.39 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.06 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {B \left (\frac {\log (i-\tan (c+d x))}{i a-b}-\frac {\log (i+\tan (c+d x))}{i a+b}+\frac {2 a^4 \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right )}-\frac {2 a \tan (c+d x)}{b^2}+\frac {\tan ^2(c+d x)}{b}\right )}{2 d} \]
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Time = 0.10 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.91
method | result | size |
derivativedivides | \(\frac {B \left (-\frac {-\frac {b \left (\tan ^{2}\left (d x +c \right )\right )}{2}+a \tan \left (d x +c \right )}{b^{2}}+\frac {-\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {a^{4} \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right )}\right )}{d}\) | \(93\) |
default | \(\frac {B \left (-\frac {-\frac {b \left (\tan ^{2}\left (d x +c \right )\right )}{2}+a \tan \left (d x +c \right )}{b^{2}}+\frac {-\frac {b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2}+a \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}+\frac {a^{4} \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right )}\right )}{d}\) | \(93\) |
parallelrisch | \(-\frac {-2 B a \,b^{3} d x -B \,a^{2} b^{2} \left (\tan ^{2}\left (d x +c \right )\right )-B \,b^{4} \left (\tan ^{2}\left (d x +c \right )\right )+B \ln \left (1+\tan ^{2}\left (d x +c \right )\right ) b^{4}-2 B \ln \left (a +b \tan \left (d x +c \right )\right ) a^{4}+2 B \,a^{3} b \tan \left (d x +c \right )+2 B a \,b^{3} \tan \left (d x +c \right )}{2 b^{3} d \left (a^{2}+b^{2}\right )}\) | \(118\) |
norman | \(\frac {\frac {B \,a^{2} x}{a^{2}+b^{2}}+\frac {B \,a^{3}}{d \,b^{3}}+\frac {b B a x \tan \left (d x +c \right )}{a^{2}+b^{2}}+\frac {B \left (\tan ^{3}\left (d x +c \right )\right )}{2 d}-\frac {B a \left (\tan ^{2}\left (d x +c \right )\right )}{2 b d}}{a +b \tan \left (d x +c \right )}+\frac {a^{4} B \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right ) d}-\frac {B b \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 d \left (a^{2}+b^{2}\right )}\) | \(152\) |
risch | \(-\frac {x B}{i b -a}+\frac {2 i B \,a^{2} x}{b^{3}}+\frac {2 i B \,a^{2} c}{b^{3} d}-\frac {2 i B x}{b}-\frac {2 i B c}{b d}-\frac {2 i a^{4} B x}{b^{3} \left (a^{2}+b^{2}\right )}-\frac {2 i a^{4} B c}{b^{3} d \left (a^{2}+b^{2}\right )}+\frac {2 B \left (-i a \,{\mathrm e}^{2 i \left (d x +c \right )}+b \,{\mathrm e}^{2 i \left (d x +c \right )}-i a \right )}{b^{2} d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) B \,a^{2}}{b^{3} d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) B}{b d}+\frac {a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) B}{b^{3} d \left (a^{2}+b^{2}\right )}\) | \(247\) |
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Time = 0.27 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.41 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {2 \, B a b^{3} d x + B a^{4} \log \left (\frac {b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) + {\left (B a^{2} b^{2} + B b^{4}\right )} \tan \left (d x + c\right )^{2} - {\left (B a^{4} - B b^{4}\right )} \log \left (\frac {1}{\tan \left (d x + c\right )^{2} + 1}\right ) - 2 \, {\left (B a^{3} b + B a b^{3}\right )} \tan \left (d x + c\right )}{2 \, {\left (a^{2} b^{3} + b^{5}\right )} d} \]
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Result contains complex when optimal does not.
Time = 1.47 (sec) , antiderivative size = 782, normalized size of antiderivative = 7.67 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\begin {cases} \tilde {\infty } B x \tan ^{3}{\left (c \right )} & \text {for}\: a = 0 \wedge b = 0 \wedge d = 0 \\\frac {B \left (x + \frac {\tan ^{3}{\left (c + d x \right )}}{3 d} - \frac {\tan {\left (c + d x \right )}}{d}\right )}{a} & \text {for}\: b = 0 \\- \frac {3 i B d x \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} - \frac {3 B d x}{2 b d \tan {\left (c + d x \right )} - 2 i b d} - \frac {2 B \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )} \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {2 i B \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {B \tan ^{3}{\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {i B \tan ^{2}{\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} - \frac {B \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} - 2 i b d} + \frac {4 i B}{2 b d \tan {\left (c + d x \right )} - 2 i b d} & \text {for}\: a = - i b \\\frac {3 i B d x \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {3 B d x}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {2 B \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )} \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {2 i B \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} + \frac {B \tan ^{3}{\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {i B \tan ^{2}{\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {B \tan {\left (c + d x \right )}}{2 b d \tan {\left (c + d x \right )} + 2 i b d} - \frac {4 i B}{2 b d \tan {\left (c + d x \right )} + 2 i b d} & \text {for}\: a = i b \\\frac {x \left (B a + B b \tan {\left (c \right )}\right ) \tan ^{4}{\left (c \right )}}{\left (a + b \tan {\left (c \right )}\right )^{2}} & \text {for}\: d = 0 \\\frac {2 B a^{4} \log {\left (\frac {a}{b} + \tan {\left (c + d x \right )} \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} - \frac {2 B a^{3} b \tan {\left (c + d x \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} + \frac {B a^{2} b^{2} \tan ^{2}{\left (c + d x \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} + \frac {2 B a b^{3} d x}{2 a^{2} b^{3} d + 2 b^{5} d} - \frac {2 B a b^{3} \tan {\left (c + d x \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} - \frac {B b^{4} \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} + \frac {B b^{4} \tan ^{2}{\left (c + d x \right )}}{2 a^{2} b^{3} d + 2 b^{5} d} & \text {otherwise} \end {cases} \]
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Time = 0.28 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.02 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {\frac {2 \, B a^{4} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{2} b^{3} + b^{5}} + \frac {2 \, {\left (d x + c\right )} B a}{a^{2} + b^{2}} - \frac {B b \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}} + \frac {B b \tan \left (d x + c\right )^{2} - 2 \, B a \tan \left (d x + c\right )}{b^{2}}}{2 \, d} \]
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Time = 0.89 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.03 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {\frac {2 \, B a^{4} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{2} b^{3} + b^{5}} + \frac {2 \, {\left (d x + c\right )} B a}{a^{2} + b^{2}} - \frac {B b \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}} + \frac {B b \tan \left (d x + c\right )^{2} - 2 \, B a \tan \left (d x + c\right )}{b^{2}}}{2 \, d} \]
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Time = 8.16 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.12 \[ \int \frac {\tan ^4(c+d x) (a B+b B \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx=\frac {B\,{\mathrm {tan}\left (c+d\,x\right )}^2}{2\,b\,d}-\frac {B\,\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )}{2\,d\,\left (b+a\,1{}\mathrm {i}\right )}-\frac {B\,a\,\mathrm {tan}\left (c+d\,x\right )}{b^2\,d}+\frac {B\,a^4\,\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )}{b^3\,d\,\left (a^2+b^2\right )}-\frac {B\,\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,1{}\mathrm {i}}{2\,d\,\left (a+b\,1{}\mathrm {i}\right )} \]
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